Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 19:38Z
\frac{11}{4} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
264K
d/dx [x^3] = 3x^2
\frac{12}{8} \sum_{i=1}^{n} i^{2}
F = ma
∑_{k=1}^{n} k = n(n+1)/2
377K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
420K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
det| 7 4 ; 4 8 | = 40
109K
∑_{k=1}^{n} k = n(n+1)/2