Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:04Z

10y² + 2y + 6 = 0

5z² + 8z + 3 = 0

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-t²) dt = √π / 2

e^{i\pi} + 1 = 0

186K

det| 10 7 ; 3 11 | = 89

411K

e^{i\pi} + 1 = 0

det| 12 1 ; 5 13 | = 151

448K

∑_{k=1}^{n} k = n(n+1)/2

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

e^{i\pi} + 1 = 0

459K

12y² + 5y + 7 = 0

406K

λ = h/p

d/dt [t^3] = 3t^2

181K

N₂ + 3H₂ ⇌ 2NH₃

80K

det| 9 4 ; 1 10 | = 86

359K

PV = nRT

455K