Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 23:35Z
11t² + 8t + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
∂ω/∂β = 7ω
∑_{k=1}^{n} k = n(n+1)/2
411K
det| 3 3 ; 7 4 | = -9
PV = nRT
det| 9 4 ; 1 10 | = 86
459K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
181K
det| 2 3 ; 5 3 | = -9
80K
det| 5 3 ; 7 6 | = 9
359K