Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 15:18Z
11n² + 5n + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
∫₀^∞ e^(-x²) dx = √π / 2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
186K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
411K
4φ² + 6φ + 2 = 0
det| 4 8 ; 3 5 | = -4
448K
∫₀^∞ e^(-φ²) dφ = √π / 2
∇²ω = 0
det| 9 5 ; 1 10 | = 85
80K
d/dr [r^2] = 2r^1
ΔS ≥ 0
8β² + 5β + 0 = 0