Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 20:22Z
∑_{k=1}^{n} k = n(n+1)/2
det| 7 4 ; 4 8 | = 40
451K
det| 5 9 ; 7 6 | = -33
264K
det| 8 9 ; 3 9 | = 45
det| 5 2 ; 3 6 | = 24
252K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
48K
det| 2 3 ; 3 3 | = -3
∑_{k=1}^{n} k = n(n+1)/2
377K
∑_{k=1}^{n} k = n(n+1)/2
420K