Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:10Z

10y² + 2y + 6 = 0

∇²r = 0

460K

∇ × E = −∂B/∂t

438K

∫₀^∞ e^(-t²) dt = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

∑_{k=1}^{n} k = n(n+1)/2

411K

e^{i\pi} + 1 = 0

∇²r = 0

448K

F = ma

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

\lim_{t\to 0} \frac{\sin t}{t} = 1

459K

det| 11 5 ; 0 12 | = 132

406K

det| 7 4 ; 4 8 | = 40

181K

PV = nRT

80K

e^{i\pi} + 1 = 0

359K

F = G m₁m₂ / r²

455K