Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 02:51Z
det| 5 4 ; 6 6 | = 6
det| 9 8 ; 3 10 | = 66
460K
∑_{k=1}^{n} k = n(n+1)/2
438K
∇²φ = 0
det| 12 5 ; 4 13 | = 136
det| 7 4 ; 4 8 | = 40
22K
∑_{k=1}^{n} k = n(n+1)/2
Fe₂O₃ + 3CO → 2Fe + 3CO₂
181K