Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 21:03Z
10y² + 2y + 6 = 0
det| 4 8 ; 3 5 | = -4
460K
det| 3 1 ; 7 4 | = 5
438K
∫₀^∞ e^(-t²) dt = √π / 2
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
22K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 7 4 ; 4 8 | = 40
406K