Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:36Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

iħ ∂ψ/∂t = Ĥψ

438K

∫₀^∞ e^(-x²) dx = √π / 2

\binom{n}{k} = \frac{n!}{k!(n-k)!}

186K

4t² + 3t + 3 = 0

411K

4φ² + 6φ + 2 = 0

8θ² + 8θ + 6 = 0

448K

e^{i\pi} + 1 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

7y² + 9y + 1 = 0

459K

d/dx [x^3] = 3x^2

406K

∇²ω = 0

det| 9 4 ; 1 10 | = 86

181K

F = G m₁m₂ / r²

80K

∫₀^∞ e^(-α²) dα = √π / 2

359K

∇ × E = −∂B/∂t

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