Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-21 09:18Z

∫₀^∞ e^(-z²) dz = √π / 2

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

262K

10ω² + 8ω + 0 = 0

N₂ + 3H₂ ⇌ 2NH₃

∑_{k=1}^{n} k = n(n+1)/2

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2H₂ + O₂ → 2H₂O

∇²z = 0

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∂y/∂n = 5y

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9r² + 6r + 7 = 0

∇²β = 0

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CaCO₃ → CaO + CO₂

331K

∑_{k=1}^{n} k = n(n+1)/2

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det| 7 4 ; 4 8 | = 40

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