Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:48Z

det| 6 5 ; 4 7 | = 22

Fe₂O₃ + 3CO → 2Fe + 3CO₂

460K

∇²θ = 0

438K

∇²φ = 0

d/dt [t^3] = 3t^2

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CH₄ + 2O₂ → CO₂ + 2H₂O

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\frac{9}{2} \sum_{i=1}^{n} i^{2}

∇ × E = −∂B/∂t

448K

6t² + 6t + 4 = 0

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F = ma

\frac{2}{2} \sum_{i=1}^{n} i^{2}

459K

8ψ² + 7ψ + 0 = 0

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