Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 19:22Z
\frac{11}{4} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
451K
∑_{k=1}^{n} k = n(n+1)/2
264K
d/dx [x^3] = 3x^2
det| 8 9 ; 4 9 | = 36
297K
\frac{12}{8} \sum_{i=1}^{n} i^{2}
det| 7 4 ; 4 8 | = 40
411K
F = ma
det| 3 7 ; 2 4 | = -2
377K
\frac{4}{6} \sum_{i=1}^{n} i^{2}
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AgNO₃ + NaCl → AgCl↓ + NaNO₃
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
401K
∫₀^∞ e^(-ψ²) dψ = √π / 2
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