Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 06:40Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
273K
e^{i\pi} + 1 = 0
∫₀^∞ e^(-α²) dα = √π / 2
108K
2H₂ + O₂ → 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
333K
det| 7 4 ; 4 8 | = 40
160K
det| 4 8 ; 0 5 | = 20
det| 5 9 ; 7 6 | = -33
413K
det| 4 7 ; 7 5 | = -29
det| 2 3 ; 5 3 | = -9
10t² + 5t + 2 = 0