Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:20Z

11n² + 5n + 4 = 0

1n² + 7n + 3 = 0

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

∇²z = 0

186K

det| 7 4 ; 4 8 | = 40

411K

4φ² + 6φ + 2 = 0

iħ ∂ψ/∂t = Ĥψ

448K

e^{i\pi} + 1 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

6x² + 6x + 1 = 0

406K

N₂ + 3H₂ ⇌ 2NH₃

181K

∫₀^∞ e^(-t²) dt = √π / 2

80K

∑_{k=1}^{n} k = n(n+1)/2

359K