Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 09:07Z
9ω² + 5ω + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
ΔS ≥ 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
186K
\oint_C \vec{F}\cdot d\vec{r} = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
448K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
406K
det| 5 9 ; 7 6 | = -33
80K
det| 7 4 ; 4 8 | = 40
359K