Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 16:20Z

∂ψ/∂φ = 6ψ

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∫₀^∞ e^(-α²) dα = √π / 2

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11ψ² + 2ψ + 6 = 0

∫₀^∞ e^(-ω²) dω = √π / 2

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det| 11 4 ; 5 12 | = 112

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λ = h/p

∑_{k=1}^{n} k = n(n+1)/2

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det| 7 4 ; 4 8 | = 40

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\frac{9}{7} \sum_{i=1}^{n} i^{2}

∑_{k=1}^{n} k = n(n+1)/2

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12γ² + 9γ + 1 = 0

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\frac{2}{8} \sum_{i=1}^{n} i^{2}

2n² + 4n + 0 = 0

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e^{i\pi} + 1 = 0

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N₂ + 3H₂ ⇌ 2NH₃

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