Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 11:37Z
∇²t = 0
∑_{k=1}^{n} k = n(n+1)/2
460K
∑_{k=1}^{n} k = n(n+1)/2
438K
det| 6 4 ; 3 7 | = 30
det| 4 8 ; 3 5 | = -4
411K
ΔS ≥ 0
1z² + 3z + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
459K
∫₀^∞ e^(-t²) dt = √π / 2
406K
7t² + 3t + 1 = 0
det| 8 3 ; 4 9 | = 60