Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:27Z

10γ² + 4γ + 3 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

det| 7 9 ; 1 8 | = 47

438K

d/dβ [β^11] = 11β^10

\lim_{t\to 0} \frac{\sin t}{t} = 1

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∫₀^∞ e^(-θ²) dθ = √π / 2

411K

3x² + 4x + 6 = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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8ψ² + 7ψ + 0 = 0

22K

CaCO₃ → CaO + CO₂

d/dt [t^3] = 3t^2

459K

10t² + 9t + 5 = 0

406K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

d/dφ [φ^1] = 1φ^0

181K

∇ × E = −∂B/∂t

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