Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z
∇²n = 0
∑_{k=1}^{n} k = n(n+1)/2
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∑_{k=1}^{n} k = n(n+1)/2
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9r² + 4r + 1 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
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∑_{k=1}^{n} k = n(n+1)/2
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\oint_C \vec{F}\cdot d\vec{r} = 0
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11γ² + 3γ + 6 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
∫₀^∞ e^(-α²) dα = √π / 2
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det| 6 1 ; 3 7 | = 39
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
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det| 9 4 ; 1 10 | = 86
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