Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:40Z

∇²t = 0

e^{i\pi} + 1 = 0

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det| 9 4 ; 1 10 | = 86

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det| 6 4 ; 3 7 | = 30

2H₂ + O₂ → 2H₂O

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2n² + 4n + 0 = 0

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ΔS ≥ 0

d/dt [t^3] = 3t^2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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1z² + 3z + 2 = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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∑_{k=1}^{n} k = n(n+1)/2

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∫₀^∞ e^(-x²) dx = √π / 2

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PV = nRT

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