Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:47Z

10y² + 2y + 6 = 0

∇ × E = −∂B/∂t

460K

∇²ω = 0

438K

∫₀^∞ e^(-t²) dt = √π / 2

\frac{4}{6} \sum_{i=1}^{n} i^{2}

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

e^{i\pi} + 1 = 0

F = G m₁m₂ / r²

448K

det| 7 4 ; 4 8 | = 40

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

6ω² + 4ω + 4 = 0

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

λ = h/p

F = G m₁m₂ / r²

181K

8θ² + 8θ + 6 = 0

80K

d/dγ [γ^3] = 3γ^2