Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 20:55Z
∑_{k=1}^{n} k = n(n+1)/2
det| 7 4 ; 4 8 | = 40
451K
∫₀^∞ e^(-t²) dt = √π / 2
264K
det| 8 9 ; 3 9 | = 45
det| 1 4 ; 3 2 | = -10
252K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
det| 9 8 ; 3 10 | = 66
411K
det| 2 3 ; 3 3 | = -3
∑_{k=1}^{n} k = n(n+1)/2
420K