Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 20:28Z
det| 6 5 ; 4 7 | = 22
∑_{k=1}^{n} k = n(n+1)/2
438K
∇²φ = 0
det| 10 2 ; 3 11 | = 104
411K
\frac{9}{2} \sum_{i=1}^{n} i^{2}
Fe₂O₃ + 3CO → 2Fe + 3CO₂
448K
F = ma
∑_{k=1}^{n} k = n(n+1)/2
406K
ΔS ≥ 0