Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:04Z

10y² + 2y + 6 = 0

∇ × E = −∂B/∂t

460K

e^{i\pi} + 1 = 0

438K

∫₀^∞ e^(-t²) dt = √π / 2

\frac{4}{6} \sum_{i=1}^{n} i^{2}

186K

∂α/∂ω = 3α

411K

e^{i\pi} + 1 = 0

∫₀^∞ e^(-θ²) dθ = √π / 2

448K

d/dt [t^3] = 3t^2

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

459K

det| 3 7 ; 2 4 | = -2

406K

λ = h/p

8ψ² + 7ψ + 0 = 0

181K

8x² + 2x + 7 = 0

80K

d/dγ [γ^3] = 3γ^2