Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 17:14Z

det| 11 2 ; 2 12 | = 128

11t² + 9t + 5 = 0

460K

∇ × E = −∂B/∂t

438K

CaCO₃ → CaO + CO₂

6r² + 3r + 1 = 0

186K

5z² + 8z + 3 = 0

411K

3θ² + 7θ + 1 = 0

iħ ∂ψ/∂t = Ĥψ

448K

e^{i\pi} + 1 = 0

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

\lim_{t\to 0} \frac{\sin t}{t} = 1

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

d/dt [t^3] = 3t^2

181K

det| 8 9 ; 4 9 | = 36

80K

det| 7 9 ; 1 8 | = 47

359K

8ψ² + 7ψ + 0 = 0

455K