Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:53Z

10y² + 2y + 6 = 0

∇ × E = −∂B/∂t

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

∫₀^∞ e^(-t²) dt = √π / 2

F = G m₁m₂ / r²

186K

6x² + 6x + 1 = 0

411K

e^{i\pi} + 1 = 0

6r² + 3r + 1 = 0

448K

det| 3 1 ; 7 4 | = 5

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

\lim_{t\to 0} \frac{\sin t}{t} = 1

459K

det| 7 4 ; 4 8 | = 40

406K

λ = h/p

iħ ∂ψ/∂t = Ĥψ

d/dγ [γ^3] = 3γ^2

CH₄ + 2O₂ → CO₂ + 2H₂O

det| 10 7 ; 2 11 | = 96