Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-21 10:00Z

6y² + 3y + 3 = 0

∑_{k=1}^{n} k = n(n+1)/2

195K

det| 9 4 ; 1 10 | = 86

262K

ΔS ≥ 0

det| 4 2 ; 6 5 | = 8

CH₄ + 2O₂ → CO₂ + 2H₂O

244K

det| 4 5 ; 4 5 | = 0

∑_{k=1}^{n} k = n(n+1)/2

231K

d/dt [t^3] = 3t^2

26K

iħ ∂ψ/∂t = Ĥψ

\binom{n}{k} = \frac{n!}{k!(n-k)!}

209K

8x² + 2x + 7 = 0

331K

∂t/∂α = 6t

ΔS ≥ 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O