Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:33Z

∇²t = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

iħ ∂ψ/∂t = Ĥψ

438K

det| 6 4 ; 3 7 | = 30

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

1n² + 7n + 3 = 0

411K

ΔS ≥ 0

∑_{k=1}^{n} k = n(n+1)/2

448K

F = G m₁m₂ / r²

22K

1z² + 3z + 2 = 0

\oint_C \vec{F}\cdot d\vec{r} = 0

459K

∂y/∂n = 5y

406K

7t² + 3t + 1 = 0

PV = nRT

181K

N₂ + 3H₂ ⇌ 2NH₃

80K

det| 8 3 ; 4 9 | = 60

det| 9 4 ; 1 10 | = 86

359K

2H₂ + O₂ → 2H₂O

455K