Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z

∇²n = 0

2n² + 4n + 0 = 0

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∇ × E = −∂B/∂t

263K

9r² + 4r + 1 = 0

det| 11 4 ; 5 12 | = 112

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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

PV = nRT

333K

e^{i\pi} + 1 = 0

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11γ² + 3γ + 6 = 0

\lim_{t\to 0} \frac{\sin t}{t} = 1

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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d/dt [t^3] = 3t^2

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4t² + 3t + 3 = 0

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CH₄ + 2O₂ → CO₂ + 2H₂O

404K

8ψ² + 7ψ + 0 = 0

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