Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:28Z

3γ² + 8γ + 4 = 0

8ψ² + 7ψ + 0 = 0

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∫₀^∞ e^(-t²) dt = √π / 2

438K

PV = nRT

d/dt [t^3] = 3t^2

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det| 11 5 ; 0 12 | = 132

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det| 1 9 ; 5 2 | = -43

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∇ × E = −∂B/∂t

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∑_{k=1}^{n} k = n(n+1)/2

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∑_{k=1}^{n} k = n(n+1)/2

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∫₀^∞ e^(-α²) dα = √π / 2

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