Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 03:04Z
∇²x = 0
∑_{k=1}^{n} k = n(n+1)/2
264K
det| 3 9 ; 1 4 | = 3
∫₀^∞ e^(-ω²) dω = √π / 2
297K
CaCO₃ → CaO + CO₂
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
48K
det| 7 4 ; 4 8 | = 40
411K
det| 8 9 ; 4 9 | = 36
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
377K
det| 12 2 ; 2 13 | = 152
299K
det| 7 6 ; 6 8 | = 20
∫₀^∞ e^(-ψ²) dψ = √π / 2
420K
det| 1 4 ; 3 2 | = -10
184K