Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 15:33Z
11n² + 5n + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
∫₀^∞ e^(-x²) dx = √π / 2
Fe₂O₃ + 3CO → 2Fe + 3CO₂
186K
CH₄ + 2O₂ → CO₂ + 2H₂O
411K
4φ² + 6φ + 2 = 0
det| 9 4 ; 1 10 | = 86
448K
∫₀^∞ e^(-φ²) dφ = √π / 2
det| 5 3 ; 7 6 | = 9
459K
∇²ω = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
181K