Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:30Z

det| 6 5 ; 4 7 | = 22

det| 5 6 ; 2 6 | = 18

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det| 9 4 ; 1 10 | = 86

438K

∇²φ = 0

det| 5 3 ; 7 6 | = 9

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∂n/∂θ = 3n

411K

\frac{9}{2} \sum_{i=1}^{n} i^{2}

d/dt [t^3] = 3t^2

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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F = ma

N₂ + 3H₂ ⇌ 2NH₃

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∑_{k=1}^{n} k = n(n+1)/2

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N₂ + 3H₂ ⇌ 2NH₃

181K

8θ² + 8θ + 6 = 0

80K