Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:05Z

10y² + 2y + 6 = 0

∂γ/∂θ = 2γ

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∫₀^∞ e^(-t²) dt = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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d/dt [t^3] = 3t^2

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e^{i\pi} + 1 = 0

det| 12 2 ; 2 13 | = 152

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iħ ∂ψ/∂t = Ĥψ

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∇²γ = 0

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\lim_{β\to 0} \frac{\sin β}{β} = 1

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det| 9 4 ; 1 10 | = 86

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e^{i\pi} + 1 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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