Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:48Z

10y² + 2y + 6 = 0

∇ × E = −∂B/∂t

460K

8ψ² + 7ψ + 0 = 0

438K

∫₀^∞ e^(-t²) dt = √π / 2

∇²r = 0

186K

\lim_{t\to 0} \frac{\sin t}{t} = 1

411K

e^{i\pi} + 1 = 0

∂y/∂γ = 8y

448K

\frac{12}{6} \sum_{i=1}^{n} i^{2}

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

e^{i\pi} + 1 = 0

459K

det| 8 9 ; 4 9 | = 36

406K

∂n/∂θ = 3n

181K

∇ × E = −∂B/∂t

80K

d/dt [t^3] = 3t^2

359K

iħ ∂ψ/∂t = Ĥψ

455K