Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 18:29Z

e^{i\pi} + 1 = 0

∑_{k=1}^{n} k = n(n+1)/2

451K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

264K

λ = h/p

8ψ² + 7ψ + 0 = 0

297K

iħ ∂ψ/∂t = Ĥψ

252K

det| 6 7 ; 7 7 | = -7

6t² + 6t + 4 = 0

48K

N₂ + 3H₂ ⇌ 2NH₃

411K

∇²ψ = 0

∫₀^∞ e^(-α²) dα = √π / 2

377K

e^{i\pi} + 1 = 0

299K

∂γ/∂γ = 9γ

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

E = mc²

Fe₂O₃ + 3CO → 2Fe + 3CO₂

det| 1 8 ; 6 2 | = -46