Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:38Z

11n² + 5n + 4 = 0

∇²β = 0

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

∇²z = 0

186K

det| 7 4 ; 4 8 | = 40

411K

4φ² + 6φ + 2 = 0

\frac{4}{6} \sum_{i=1}^{n} i^{2}

448K

10t² + 9t + 5 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

det| 4 8 ; 3 5 | = -4

459K

N₂ + 3H₂ ⇌ 2NH₃

406K

∇ × E = −∂B/∂t

181K

PV = nRT

80K

F = G m₁m₂ / r²

359K