Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:41Z

10γ² + 4γ + 3 = 0

F = ma

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

d/dβ [β^11] = 11β^10

∂x/∂ψ = 6x

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

3x² + 4x + 6 = 0

6t² + 6t + 4 = 0

448K

d/dt [t^3] = 3t^2

22K

CaCO₃ → CaO + CO₂

11t² + 9t + 7 = 0

459K

iħ ∂ψ/∂t = Ĥψ

406K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

∑_{k=1}^{n} k = n(n+1)/2

181K

∫₀^∞ e^(-ψ²) dψ = √π / 2

80K

det| 9 4 ; 1 10 | = 86

359K

det| 5 2 ; 3 6 | = 24

455K