Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:38Z

11n² + 5n + 4 = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

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∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

N₂ + 3H₂ ⇌ 2NH₃

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\frac{4}{9} \sum_{i=1}^{n} i^{2}

411K

4φ² + 6φ + 2 = 0

det| 7 4 ; 4 8 | = 40

448K

iħ ∂ψ/∂t = Ĥψ

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4t² + 3t + 3 = 0

459K

det| 5 2 ; 3 6 | = 24

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\frac{2}{2} \sum_{i=1}^{n} i^{2}

181K

∇²z = 0

80K

10t² + 9t + 5 = 0

359K