Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 19:41Z

CH₄ + 2O₂ → CO₂ + 2H₂O

∂x/∂ψ = 6x

460K

∫₀^∞ e^(-z²) dz = √π / 2

438K

det| 1 1 ; 4 2 | = -2

iħ ∂ψ/∂t = Ĥψ

186K

8ψ² + 7ψ + 0 = 0

411K

CaCO₃ → CaO + CO₂

det| 10 2 ; 3 11 | = 104

448K

∇²ω = 0

22K

det| 8 4 ; 2 9 | = 64

\lim_{t\to 0} \frac{\sin t}{t} = 1

459K

N₂ + 3H₂ ⇌ 2NH₃

406K

7γ² + 8γ + 3 = 0

181K

∫₀^∞ e^(-α²) dα = √π / 2

80K

\lim_{t\to 0} \frac{\sin t}{t} = 1

359K

CH₄ + 2O₂ → CO₂ + 2H₂O

455K