Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 02:49Z

det| 5 4 ; 6 6 | = 6

d/dt [t^3] = 3t^2

460K

∇ × E = −∂B/∂t

438K

∇²φ = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

186K

e^{i\pi} + 1 = 0

411K

det| 12 5 ; 4 13 | = 136

\lim_{r\to 0} \frac{\sin r}{r} = 1

448K

N₂ + 3H₂ ⇌ 2NH₃

22K

∑_{k=1}^{n} k = n(n+1)/2

∫₀^∞ e^(-x²) dx = √π / 2

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

CaCO₃ → CaO + CO₂

8ψ² + 7ψ + 0 = 0

181K

E = mc²

ω = 2πf

CH₄ + 2O₂ → CO₂ + 2H₂O