Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:37Z

10y² + 2y + 6 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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8ψ² + 7ψ + 0 = 0

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∫₀^∞ e^(-t²) dt = √π / 2

iħ ∂ψ/∂t = Ĥψ

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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e^{i\pi} + 1 = 0

∫₀^∞ e^(-t²) dt = √π / 2

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N₂ + 3H₂ ⇌ 2NH₃

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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det| 5 2 ; 3 6 | = 24

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