Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:02Z

det| 6 5 ; 4 7 | = 22

∇ × E = −∂B/∂t

460K

6ω² + 4ω + 4 = 0

438K

∇²φ = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

d/dt [t^3] = 3t^2

411K

\frac{9}{2} \sum_{i=1}^{n} i^{2}

8ψ² + 7ψ + 0 = 0

448K

\frac{4}{9} \sum_{i=1}^{n} i^{2}

22K

F = ma

∇²ω = 0

459K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

406K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

181K

∇ × E = −∂B/∂t

80K