Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 22:37Z

N₂ + 3H₂ ⇌ 2NH₃

10t² + 9t + 5 = 0

246K

det| 7 4 ; 4 8 | = 40

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9ψ² + 4ψ + 2 = 0

det| 3 1 ; 7 4 | = 5

43K

PV = nRT

261K

d/dβ [β^6] = 6β^5

10ω² + 7ω + 4 = 0

424K

∑_{k=1}^{n} k = n(n+1)/2

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det| 6 1 ; 4 7 | = 38

iħ ∂ψ/∂t = Ĥψ

41K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

298K

\frac{6}{5} \sum_{i=1}^{n} i^{2}

N₂ + 3H₂ ⇌ 2NH₃

447K

∑_{k=1}^{n} k = n(n+1)/2

297K

d/dφ [φ^1] = 1φ^0

112K

∇ × E = −∂B/∂t

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