Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:40Z

10y² + 2y + 6 = 0

∫₀^∞ e^(-θ²) dθ = √π / 2

460K

det| 5 2 ; 3 6 | = 24

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∫₀^∞ e^(-t²) dt = √π / 2

ΔS ≥ 0

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8ψ² + 7ψ + 0 = 0

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e^{i\pi} + 1 = 0

d/dt [t^3] = 3t^2

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iħ ∂ψ/∂t = Ĥψ

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∇ × E = −∂B/∂t

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∑_{k=1}^{n} k = n(n+1)/2

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∇²z = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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