Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:57Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

∇²β = 0

186K

F = G m₁m₂ / r²

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4φ² + 6φ + 2 = 0

∂γ/∂z = 6γ

448K

det| 9 4 ; 1 10 | = 86

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∫₀^∞ e^(-φ²) dφ = √π / 2

iħ ∂ψ/∂t = Ĥψ

459K

\lim_{t\to 0} \frac{\sin t}{t} = 1

406K

7r² + 8r + 5 = 0

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