Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 01:32Z

11φ² + 9φ + 3 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∫₀^∞ e^(-θ²) dθ = √π / 2

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∫₀^∞ e^(-y²) dy = √π / 2

7r² + 8r + 5 = 0

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12y² + 5y + 7 = 0

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\lim_{y\to 0} \frac{\sin y}{y} = 1

iħ ∂ψ/∂t = Ĥψ

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N₂ + 3H₂ ⇌ 2NH₃

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8ψ² + 7ψ + 0 = 0

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∇²r = 0

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9ψ² + 7ψ + 3 = 0

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N₂ + 3H₂ ⇌ 2NH₃

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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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