Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:49Z

det| 6 5 ; 4 7 | = 22

d/dt [t^3] = 3t^2

460K

∇ × E = −∂B/∂t

438K

∇²φ = 0

8ψ² + 7ψ + 0 = 0

186K

det| 5 9 ; 7 6 | = -33

411K

\frac{9}{2} \sum_{i=1}^{n} i^{2}

E = mc²

448K

\frac{2}{2} \sum_{i=1}^{n} i^{2}

22K

F = ma

iħ ∂ψ/∂t = Ĥψ

459K

det| 4 7 ; 2 5 | = 6

406K

ΔS ≥ 0

AgNO₃ + NaCl → AgCl↓ + NaNO₃