Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 21:52Z

E = mc²

8ψ² + 7ψ + 0 = 0

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\frac{8}{7} \sum_{i=1}^{n} i^{2}

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e^{i\pi} + 1 = 0

d/dt [t^3] = 3t^2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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iħ ∂ψ/∂t = Ĥψ

\lim_{t\to 0} \frac{\sin t}{t} = 1

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∇ × E = −∂B/∂t

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∇²β = 0

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∑_{k=1}^{n} k = n(n+1)/2

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∫₀^∞ e^(-x²) dx = √π / 2

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