Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 22:06Z

3n² + 7n + 7 = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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∇ × E = −∂B/∂t

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∫₀^∞ e^(-ω²) dω = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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iħ ∂ψ/∂t = Ĥψ

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\frac{10}{6} \sum_{i=1}^{n} i^{2}

d/dt [t^3] = 3t^2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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d/dr [r^12] = 12r^11

iħ ∂ψ/∂t = Ĥψ

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8ψ² + 7ψ + 0 = 0

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N₂ + 3H₂ ⇌ 2NH₃

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∫₀^∞ e^(-t²) dt = √π / 2

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